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  1. #
  2. # Test of update statement that uses many tables,
  3. # --max_heap_table_size=1
  4. #
  5. --disable_warnings
  6. drop table if exists t1, t2;
  7. --enable_warnings
  8. --echo #
  9. --echo # Bug #36676: multiupdate using LEFT JOIN updates only
  10. --echo # first row or fails with an error:
  11. --echo # ERROR 1022 (23000): Can't write; duplicate key in table ''
  12. --echo #
  13. --echo
  14. --echo #
  15. --echo # Multiupdate creates MyISAM temporary table without MEMORY table
  16. --echo #
  17. CREATE TABLE t1 (ID INT);
  18. CREATE TABLE t2 (ID INT,
  19. s1 TEXT, s2 TEXT, s3 VARCHAR(10), s4 TEXT, s5 VARCHAR(10));
  20. INSERT INTO t1 VALUES (1),(2);
  21. INSERT INTO t2 VALUES (1,'test', 'test', 'test', 'test', 'test'),
  22. (2,'test', 'test', 'test', 'test', 'test');
  23. SELECT * FROM t1 LEFT JOIN t2 USING(ID);
  24. UPDATE t1 LEFT JOIN t2 USING(ID) SET s1 = 'changed';
  25. UPDATE t1 JOIN t2 USING(ID) SET s2 = 'changed';
  26. UPDATE t1 LEFT JOIN t2 USING(ID) SET s3 = 'changed';
  27. UPDATE t1 LEFT JOIN t2 USING(ID) SET s4 = 'changed', s5 = 'changed';
  28. SELECT * FROM t1 LEFT JOIN t2 USING(ID);
  29. DROP TABLE t1, t2;
  30. --echo #
  31. --echo # Multiupdate creates temporary MyISAM table from MEMORY table
  32. --echo #
  33. CREATE TABLE t1 (id INT NOT NULL AUTO_INCREMENT PRIMARY KEY);
  34. CREATE TABLE t2 (id INT, s1 CHAR(255));
  35. # insert [1..64] into table `t1`
  36. INSERT INTO t1 VALUES (0), (0), (0), (0), (0), (0), (0), (0);
  37. INSERT INTO t1 (SELECT 0 FROM t1);
  38. INSERT INTO t1 (SELECT 0 FROM t1);
  39. INSERT INTO t1 (SELECT 0 FROM t1);
  40. INSERT INTO t2 (SELECT ID, 'a' FROM t1);
  41. UPDATE t1 LEFT JOIN t2 USING(id) SET s1 = 'b';
  42. SELECT DISTINCT s1 FROM t1 LEFT JOIN t2 USING(id);
  43. DROP TABLE t1, t2;
  44. --echo # End of 5.0 tests